JEE Mains · Physics · STD 12 - 13. Nuclei
An atom \({ }_3^8 X\) is bombarded by shower of fundamental particles and in 10 s this atom absorbed 10 electrons, 10 protons and 9 neutrons. The percentage growth in the surface area of the nucleons is recorded by :
- A 250%
- B 150%
- C 225%
- D 900%
Answer & Solution
Correct Answer
(C) 225%
Step-by-step Solution
Detailed explanation
Surface area \(x \propto A ^{2 / 3}\) \(X_i=8^{2 / 3} K=4 K\) \(X_f=(8+10+9)^{2 / 3} K=9 K\) % increase in surface area of nucleus \(x_i=\frac{9 K-4 K}{4 K} \times 100=125\) %
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