JEE Mains · Physics · STD 11 - 9.1 fluid mechanics
A spherical liquid drop of radius \(R\) acquires the terminal velocity \(v_1\) when falls through a gas of viscosity \(\eta\). Now the drop is broken into \(64\) identical droplets and each droplet acquires terminal velocity \(v_2\) falling through the same gas. The ratio of terminal velocities \(v_1/v_2\) is ________.
- A \(4\)
- B \(0.25\)
- C \(32\)
- D \(16\)
Answer & Solution
Correct Answer
(D) \(16\)
Step-by-step Solution
Detailed explanation
The terminal velocity of a spherical drop of radius \(r\) falling through a viscous medium is given by Stokes' law: \(v = \dfrac{2}{9} \dfrac{r^2 (\rho - \sigma) g}{\eta}\) From this relation, the terminal velocity is directly proportional to the square of the radius of the…
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