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JEE Mains · Physics · STD 11 - Fluid mechanics
  • JEE Mains 2021
  • Medium
  • MCQ

In Millikan's oil drop experiment, what is viscous force acting on an uncharged drop of radius \(2.0 \times 10^{-5}\, {m}\) and density \(1.2 \times 10^{3} \,{kgm}^{-3}\) ? Take viscosity of liquid \(=1.8 \times 10^{-5}\, {Nsm}^{-2} .\) (Neglect buoyancy due to air).

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Answer & Solution

Correct Answer

(B) \(3.9 \times 10^{-10}\, {N}\)

Step-by-step Solution

Detailed explanation

Viscous force \(=\) Weight

\(=\rho \times\left(\frac{4}{3} \pi^{3}\right) \,g\)

\(=3.9 \times 10^{-10}\)

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