JEE Mains · Physics · STD 11 - Fluid mechanics
- JEE Mains 2021
- Medium
- MCQ
In Millikan's oil drop experiment, what is viscous force acting on an uncharged drop of radius \(2.0 \times 10^{-5}\, {m}\) and density \(1.2 \times 10^{3} \,{kgm}^{-3}\) ? Take viscosity of liquid \(=1.8 \times 10^{-5}\, {Nsm}^{-2} .\) (Neglect buoyancy due to air).
Pick an option to check your answer.
Answer & Solution
Correct Answer
(B) \(3.9 \times 10^{-10}\, {N}\)
Step-by-step Solution
Detailed explanation
Viscous force \(=\) Weight
\(=\rho \times\left(\frac{4}{3} \pi^{3}\right) \,g\)
\(=3.9 \times 10^{-10}\)
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