ExamBro
ExamBro
JEE Mains · Physics · STD 11 - 9.1 fluid mechanics

In Millikan's oil drop experiment, what is viscous force acting on an uncharged drop of radius \(2.0 \times 10^{-5}\, {m}\) and density \(1.2 \times 10^{3} \,{kgm}^{-3}\) ? Take viscosity of liquid \(=1.8 \times 10^{-5}\, {Nsm}^{-2} .\) (Neglect buoyancy due to air).

  1. A \(3.8 \times 10^{-11}\, {N}\)
  2. B \(3.9 \times 10^{-10}\, {N}\)
  3. C \(1.8 \times 10^{-10} \,{N}\)
  4. D \(5.8 \times 10^{-10} \,{N}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(3.9 \times 10^{-10}\, {N}\)

Step-by-step Solution

Detailed explanation

Viscous force \(=\) Weight \(=\rho \times\left(\frac{4}{3} \pi^{3}\right) \,g\) \(=3.9 \times 10^{-10}\)
Same subject
Explore more questions on app
From JEE Mains
Explore more questions on app