JEE Mains · Physics · STD 12 - Electric charges and fields
- JEE Mains 2017
- Hard
- Numerical
An electric dipole has a fixed dipole moment \(\vec P\) which makes angle \(\theta \) with respect to \(x-\)axis. When subjected to an electric field \(\overrightarrow {{E_1}} \) \(=E\)\(\hat i\) it experiences a torque \(\overrightarrow {{T_1}} \) =\(\;\tau \hat k\) When subjected to another electric field \(\overrightarrow {{E_2}} = \sqrt 3 {E_1}\hat j\) it experiences torque \(\overrightarrow {{T_2}} \) = \( - \overrightarrow {{T_1}} \) The angle \(\theta \;\) is.......\(^o\)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(C) \(60\)
Step-by-step Solution
Detailed explanation
\(\mathrm{T}=\mathrm{PE} \sin \theta\) Torque experienced by the dipole in an electric field,
\(\quad \vec{T}=\vec{P} \times \vec{E}\)
\(\vec{p}=p \cos \theta \hat{i}+p \sin \theta \hat{j}\)
\(\vec{E}_{1}=\overrightarrow{E i}\)
\(\vec{T}_{1}=\vec{p} \times \vec{E}_{1}=(p \cos \theta \hat{i}+p \sin \theta \hat{j}) \times E(\hat{i})\)
\(\tau \hat{k}=p E \sin \theta(-\hat{k}).........(i)\)
\(\vec{E}_{2}=\sqrt{3} E_{1} \hat{j}\)
\(\left.\vec{T}_{2}=p \cos \theta \hat{i}+p \sin \theta \hat{j}\right) \times \sqrt{3} E_{1} \hat{j}\)
\(\tau \hat{k}=\sqrt{3} p E_{1} \cos \theta \hat{k}.........(ii)\)
From eqns. ( \(i\) ) and \((ii )\)
\(p E \sin \theta=\sqrt{3} p E \cos \theta\)
\(\tan \theta=\sqrt{3} \quad \therefore \quad \theta=60^{\circ}\)
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