JEE Mains · Physics · STD 11 - Units,dimensions and measurement
- JEE Mains 2023
- Hard
- MCQ
In the equation \(\left[X+\frac{a}{Y^2}\right][Y-b]= R T, X\) is pressure, \(Y\) is volume, \(R\) is universal gas constant and \(T\) is temperature. The physical quantity equivalent to the ratio \(\frac{a}{b}\) is
Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) Energy
Step-by-step Solution
Detailed explanation
\(X\) and \(\frac{a}{Y^2}\) have same dimensions
\(Y\) and \(b\) have same dimensions
\(\therefore[a] =\left[ ML ^5 T ^{-2}\right]\)
\({[b] } =\left[ L ^3\right]\)
\(\frac{[a]}{[b]} =\left[ ML ^2 T ^{-2}\right] \text { has dimensions of energy }\)
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