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JEE Mains · Physics · STD 12 - Atoms
  • JEE Mains 2024
  • Hard
  • MCQ

According to Bohr's theory, the moment of momentum of an electron revolving in \(4^{\text {th }}\) orbit of hydrogen atom is _______.

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Answer & Solution

Correct Answer

(C) \(2 \frac{\mathrm{h}}{\pi}\)

Step-by-step Solution

Detailed explanation

Moment of momentum is \(\vec{r} \times \vec{P}\)

\(\overrightarrow{\mathrm{L}}=\overrightarrow{\mathrm{r}} \times \mathrm{m} \overrightarrow{\mathrm{v}}\)

\(\mathrm{L}=\mathrm{mvr}=\frac{\mathrm{nh}}{2 \pi}=\frac{4 \mathrm{~h}}{2 \pi}=\frac{2 \mathrm{~h}}{\pi}\)

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