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JEE Mains · Physics · STD 11 - 10.1, thermonetry,thermal expansion and calorimetry
  • JEE Mains 2026
  • Hard
  • MCQ

10 kg of ice at \(-10^{\circ}C\) is added to 100 kg of water to lower its temperature from \(25^{\circ}C.\) Consider no heat exchange to surroundings. The decrement to the temperature of water is ___________ \(^{\circ}C.\)
(specific heat of ice \(= 2100\ J/Kg.^{\circ}C\), specific heat of water \(= 4200\ J/Kg.^{\circ}C\), latent heat of fusion of ice \(= 3.36 \times 10^{5}\ J/Kg\))

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Answer & Solution

Correct Answer

(A) 10

Step-by-step Solution

Detailed explanation

\(10 \times 3.36 \times 10^5+10 \times 2100 \times 10+10 \times 4200 \times(T-0)\)
\(=100 \times 4200 \times(25- T )\)
\(\Rightarrow T =15^{\circ} C\)
\(\Delta T =25-15=10^{\circ} C\)
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