JEE Mains · Physics · STD 11 - 10.1, thermonetry,thermal expansion and calorimetry
10 kg of ice at \(-10^{\circ}C\) is added to 100 kg of water to lower its temperature from \(25^{\circ}C.\) Consider no heat exchange to surroundings. The decrement to the temperature of water is ___________ \(^{\circ}C.\)
(specific heat of ice \(= 2100\ J/Kg.^{\circ}C\), specific heat of water \(= 4200\ J/Kg.^{\circ}C\), latent heat of fusion of ice \(= 3.36 \times 10^{5}\ J/Kg\))
- A 10
- B 15
- C 6.67
- D 11.6
Answer & Solution
Correct Answer
(A) 10
Step-by-step Solution
Detailed explanation
\(10 \times 3.36 \times 10^5+10 \times 2100 \times 10+10 \times 4200 \times(T-0)\) \(=100 \times 4200 \times(25- T )\) \(\Rightarrow T =15^{\circ} C\) \(\Delta T =25-15=10^{\circ} C\)
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