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JEE Mains · Physics · STD 11 - Friction
  • JEE Mains 2022
  • Medium
  • MCQ

A block of mass \(10\, kg\) starts sliding on a surface with an initial velocity of \(9.8\, ms ^{-1}\). The coefficient of friction between the surface and bock is \(0.5\). The distance covered by the block before coming to rest is: [use \(g =9.8\, ms ^{-2}\) ].........\(m\)

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Answer & Solution

Correct Answer

(B) \(9.8\)

Step-by-step Solution

Detailed explanation

\(a =-\mu g =-0.5 \times 9.8=-4.9\) \(m / s ^{2}\)

\(d =\frac{ v ^{2}}{2 a }=\frac{9.8 \times 9.8}{2(4.9)}\)

\(=9.8\, m\)

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