JEE Mains · Physics · STD 11 - 3.2 motion in plane
Two projectile thrown at \(30^{\circ}\) and \(45^{\circ}\) with the horizontal respectively, reach the maximum height in same time. The ratio of their initial velocities is
- A \(1: \sqrt{2}\)
- B \(2: 1\)
- C \(\sqrt{2}: 1\)
- D \(1: 2\)
Answer & Solution
Correct Answer
(C) \(\sqrt{2}: 1\)
Step-by-step Solution
Detailed explanation
Time taken to reach maximum height \(t =\frac{ u \sin \theta}{ g }\) \(\therefore \frac{ u _{1} \sin \theta_{1}}{ g }=\frac{ u _{2} \sin \theta_{2}}{ g }\) \(\Rightarrow u _{1} \sin 30= u _{2} \sin 45\)…
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