JEE Mains · Physics · STD 11 - Motion in plane
- JEE Mains 2022
- Medium
- MCQ
Two projectile thrown at \(30^{\circ}\) and \(45^{\circ}\) with the horizontal respectively, reach the maximum height in same time. The ratio of their initial velocities is
Pick an option to check your answer.
Answer & Solution
Correct Answer
(C) \(\sqrt{2}: 1\)
Step-by-step Solution
Detailed explanation
Time taken to reach maximum height
\(t =\frac{ u \sin \theta}{ g }\)
\(\therefore \frac{ u _{1} \sin \theta_{1}}{ g }=\frac{ u _{2} \sin \theta_{2}}{ g }\)
\(\Rightarrow u _{1} \sin 30= u _{2} \sin 45\)
\(\Rightarrow \frac{ u _{1}}{ u _{2}}=\frac{1 / \sqrt{2}}{1 / 2}=\frac{\sqrt{2}}{1}\)
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