JEE Mains · Physics · STD 11 - 9.2 surface tension
If \(‘M’\) is the mass of water that rises in a capillary tube of radius \(‘r’,\) then mass of water which will rise in a capillary tube of radius \(‘2r’\) is
- A \(4\,M\)
- B \(\frac {M}{2}\)
- C \(M\)
- D \(2\,M\)
Answer & Solution
Correct Answer
(D) \(2\,M\)
Step-by-step Solution
Detailed explanation
Height of liquid rise in capillary tube \(h = \frac{{2T\cos {\theta _c}}}{{\rho rg}}\) \( \Rightarrow h \propto \frac{1}{r}\) When radius becomes double height become half \(\therefore h' = \frac{h}{2}\) \(Now,\,M = \pi {r^2}h \times \rho \,and\,M'\)…
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