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JEE Mains · Physics · STD 11 - 9.2 surface tension

The ratio of surface tensions of mercury and water is given to be \(7.5\) while the ratio of their densities is \(13.6\). Their contact angles, with glass, are close to \(135^o\) and \(0^o\), respectively. It is observed that mercury gets depressed by an amount \(h\) in a capillary tube of radius \(r_1\), while water rises by the same amount \(h\) in a capillary tube of radius \(r_2\). The ratio, \((r_1/r_2)\), is then close to

  1. A \(3/5\)
  2. B \(4/5\)
  3. C \(2/3\)
  4. D \(2/5\)
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Answer & Solution

Correct Answer

(D) \(2/5\)

Step-by-step Solution

Detailed explanation

\(h = \frac{{2{S_1}\cos \theta }}{{{r_1}{\rho _1}g}}\) \(h = \frac{{2{s_2}\cos {\theta _2}}}{{{r_2}{\rho _2}g}}\) \( \Rightarrow \frac{{{r_1}}}{{{r_2}}} = \frac{2}{5}\)
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