JEE Mains · Physics · STD 11 - 9.2 surface tension
The ratio of surface tensions of mercury and water is given to be \(7.5\) while the ratio of their densities is \(13.6\). Their contact angles, with glass, are close to \(135^o\) and \(0^o\), respectively. It is observed that mercury gets depressed by an amount \(h\) in a capillary tube of radius \(r_1\), while water rises by the same amount \(h\) in a capillary tube of radius \(r_2\). The ratio, \((r_1/r_2)\), is then close to
- A \(3/5\)
- B \(4/5\)
- C \(2/3\)
- D \(2/5\)
Answer & Solution
Correct Answer
(D) \(2/5\)
Step-by-step Solution
Detailed explanation
\(h = \frac{{2{S_1}\cos \theta }}{{{r_1}{\rho _1}g}}\) \(h = \frac{{2{s_2}\cos {\theta _2}}}{{{r_2}{\rho _2}g}}\) \( \Rightarrow \frac{{{r_1}}}{{{r_2}}} = \frac{2}{5}\)
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