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JEE Mains · Physics · STD 11 - 9.2 surface tension
When a long glass capillary tube of radius \(0.015\;cm\) is dipped in a liquid, the liquid rises to a height of \(15\, cm\) within it. If the contact angle between the liquid and glass to clase to \(0^{\circ},\) the surface tension of the liquid, in \(milli\,Newton \;m ^{-1}\) is \(.....\) \(\left[\rho_{\text {(liquid) }}=900\; kg\,m ^{-3}, g =10\, ms ^{-2}\right]\) (Give answer in closest integer)
- A \(115\)
- B \(120\)
- C \(101\)
- D \(109\)
Answer & Solution
Correct Answer
(C) \(101\)
Step-by-step Solution
Detailed explanation
Capillary rise \(h =\frac{2 S \cos \theta}{\rho gr }\) \(S=\frac{\rho grh}{2 \cos \theta}\) \(=\frac{(900)(10)\left(15 \times 10^{-5}\right)\left(15 \times 10^{-2}\right)}{2}\) \(S=1012.5 \times 10^{-4}\) \(S=101.25 \times 10^{-3}=101.25 mN / m\) In question closest integer is…
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