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JEE Mains · Physics · STD 12 -7. Alternating current

For a series \(LCR\) circuit, \(I\) vs \(\omega\) curve is shown \((A)\) To the left of \(\omega_{r}\), the circuit is mainly capacitive. \((B)\) To the left of \(\omega_{r}\), the circuit is mainly inductive. \((C)\) At \(\omega_{r}\), impedance of the circuit is equal to the resistance of the circuit. \((D)\) At \(\omega_{t}\), impedance of the circuit is \(0\). Choose the most appropriate answer from the options given below

  1. A \((a)\) and \((d)\) only
  2. B \((b)\) and \((d)\) only
  3. C \((a)\) and \((c)\) only
  4. D \((b)\) and \((c)\) only
Verified Solution

Answer & Solution

Correct Answer

(C) \((a)\) and \((c)\) only

Step-by-step Solution

Detailed explanation

\(\text { at } \omega_{r}, X_{C}=X_{L}\) \(\Rightarrow \frac{1}{\omega_{r} C}=\omega_{r} L\) So if \(\omega < \omega_{r}\) then \(X_{C}\) will increase and \(X_{L}\) will decrease. Hence to left of \(\omega_{t}\) circuit is capacitive…
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