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JEE Mains · Physics · STD 11 - Fluid mechanics
  • JEE Mains 2023
  • Hard
  • Numerical

Eight equal drops of water are falling through air with a steady speed of \(10\,cm / s\). If the drops coalesce, the new velocity is \(.........\,cm/s\)

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Answer & Solution

Correct Answer

(B) \(40\)

Step-by-step Solution

Detailed explanation

\(v \propto r ^2\)

\(\frac{ v _1}{ v _2}=\left(\frac{ r }{ R }\right)^2\)

\(8 \cdot \frac{4}{3} \pi r ^3=\frac{4}{3} \pi R ^3\)

\(R =2 r\)

\(\frac{10}{ v _2}=\left(\frac{1}{2}\right)^2\)

\(v _2=40\,cm / s\)

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