JEE Mains · Physics · STD 11 - 6. system of particles and rotational motion
Two coaxial discs, having moments of inertia \(I_1\) and \(\frac{I_1}{2}\) are a rotating with respectively angular velocities \(\omega_1\) and \(\frac{\omega_1}{2}\), about their common axes. They are brought in contact with each other and thereafter they rotate with a common angular velocity. If \(E_f\) and \(E_i\) are the final and initial total energies, then \((E_f -E_i)\) is
- A \(\frac{{{I_1}\omega _1^2}}{6}\)
- B \(\frac{3}{8}{I_1}\omega _1^2\)
- C \( - \frac{{{I_1}\omega _1^2}}{{12}}\)
- D \( - \frac{{{I_1}\omega _1^2}}{{24}}\)
Answer & Solution
Correct Answer
(D) \( - \frac{{{I_1}\omega _1^2}}{{24}}\)
Step-by-step Solution
Detailed explanation
\({E_i} = \frac{1}{2}{I_1} \times \omega _1^2 + \frac{1}{2}\frac{I}{2} \times \frac{{\omega _1^2}}{4}\) \( = \frac{{{I_1}\omega _1^2}}{2}\left( {\frac{9}{8}} \right) = \frac{9}{{16}}{I_1}\omega _1^2\)…
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