JEE Mains · Physics · STD 12 - Ray optics and optical instruments
- JEE Mains 2014
- Hard
- MCQ
A diver looking up through the water sees the outside world contained in a circular horizon. The refractive index of water is \(\frac{4}{3}\), and the diver's eyes are \(15\, cm\) below the surface of water. Then the radius of the circle is
Pick an option to check your answer.
Answer & Solution
Correct Answer
(D) \(\frac{{15 \times 3}}{{\sqrt 7 }}\,\,cm\)
Step-by-step Solution
Detailed explanation
Given, \(\mu \, = \,\frac{4}{3}\)
\(h\,=\,15\,cm\)
\(R\,=\,?\)
\(\frac{\sin 90^o}{\sin C}=\mu\)
\(\Rightarrow \quad \sin C=\frac{1}{\mu}=\frac{R}{\sqrt{R^{2}+h^{2}}}=\frac{3}{4}\)
\(\Rightarrow \quad 16 R^{2}=9 R^{2}+9 h^{2}\)
or, \({7{R^2} = 9{h^2}}\)
or, \({R = \frac{3}{{\sqrt 7 }}h = \frac{3}{{\sqrt 7 }} \times 15\,\,{\text{cm}}}\)
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