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JEE Mains · Physics · STD 12 - Ray optics and optical instruments
  • JEE Mains 2014
  • Hard
  • MCQ

A diver looking up through the water sees the outside world contained in a circular horizon. The refractive index of water is \(\frac{4}{3}\),  and the diver's eyes are \(15\, cm\) below the surface of water. Then the radius of the circle is

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Answer & Solution

Correct Answer

(D) \(\frac{{15 \times 3}}{{\sqrt 7 }}\,\,cm\)

Step-by-step Solution

Detailed explanation

Given, \(\mu \, = \,\frac{4}{3}\)

\(h\,=\,15\,cm\)

\(R\,=\,?\)

\(\frac{\sin 90^o}{\sin C}=\mu\)

\(\Rightarrow \quad \sin C=\frac{1}{\mu}=\frac{R}{\sqrt{R^{2}+h^{2}}}=\frac{3}{4}\)

\(\Rightarrow \quad 16 R^{2}=9 R^{2}+9 h^{2}\)

or,   \({7{R^2} = 9{h^2}}\)

or,   \({R = \frac{3}{{\sqrt 7 }}h = \frac{3}{{\sqrt 7 }} \times 15\,\,{\text{cm}}}\)

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