ExamBro
ExamBro
JEE Mains · Physics · STD 11 - Units,dimensions and measurement
  • JEE Mains 2023
  • Medium
  • MCQ

Match List \(I\) with List \(II\)
LIST\(-I\) LIST\(-II\)
\((A)\) Surface tension \((I)\) \(Kg m ^{-1} s ^{-1}\)
\((B)\) Pressure \((II)\) \(Kg ms^{-1 }\)
\((C)\) Viscosity \((III)\) \(Kg m ^{-1} s ^{-2}\)
\((D)\) Impulse \((IV)\) \(Kg s ^{-2}\)
Choose the correct answer from the options given below :

Pick an option to check your answer.
Verified Solution

Answer & Solution

Correct Answer

(B) \((A)-(IV), (B)-(III), (C)-(I), (D)-(II)\)

Step-by-step Solution

Detailed explanation

\((A)\) Surface Tension \(=\frac{ F }{\ell}=\frac{ MLT ^{-2}}{ L }= ML ^{-1} T ^{-2}\)

\(= Kgs ^{-2}( IV )\)

\((B)\) Pressure \(=\frac{ F }{ A }=\frac{ MLT ^{-2}}{ L ^2}\)

\(= kg m ^{-1} s ^{-2}\) (III)

\((C)\) Viscosity \(==\frac{ F }{ A \left(\frac{ dV }{ dz }\right)}=\frac{ MLT ^{-2}}{ L ^2\left(\frac{ LT ^{-1}}{ L }\right)}\)

\(= ML ^{-1} T ^{-1}= kg m ^{-1} s ^{-1}\) (I)

\((D)\) Impulse \(=\int Fdt = MLT ^{-2} \times T\)

\(= MLT ^{-1}= Kgms ^{-1}( II )\)

Same subject
Explore more questions on app