• JEE Mains 2021
• Medium
• MCQ

Asseretion \(A:\) If in five complete rotations of the circular scale, the distance travelled on main scale of the screw gauge is \(5\, {mm}\) and there are \(50\) total divisions on circular scale, then least count is \(0.001\, {cm}\). Reason \(R:\) Least Count \(=\frac{\text { Pitch }}{\text { Total divisions on circular scale }}\) In the light of the above statements, choose the most appropriate answer from the options given below:

1. A

   Both \(A\) and \(R\) are correct and \(R\) is the correct explanation of \(A\)

2. B \(A\) is not correct but \(R\) is correct.
3. C Both \(A\) and \(R\) are correct and \(R\) is NOT the correct explanation of \(A\).
4. D \({A}\) is correct but \({R}\) is not correct.