JEE Mains · Physics · STD 12 - 14. Semicondutor electronics
Find the truth table for the function \(Y\) and \(A\) and \(B\) represented in the following figure.
- A
\(A\) \(B\) \(Y\) \(0\) \(0\) \(0\) \(0\) \(1\) \(1\) \(1\) \(0\) \(0\) \(1\) \(1\) \(1\) - B
\(A\) \(B\) \(Y\) \(0\) \(0\) \(1\) \(0\) \(1\) \(0\) \(1\) \(0\) \(1\) \(1\) \(1\) \(1\) - C
\(A\) \(B\) \(Y\) \(0\) \(0\) \(0\) \(0\) \(1\) \(0\) \(1\) \(0\) \(0\) \(1\) \(1\) \(1\) - D
\(A\) \(B\) \(Y\) \(0\) \(0\) \(0\) \(0\) \(1\) \(1\) \(1\) \(0\) \(1\) \(1\) \(1\) \(1\)
Answer & Solution
Correct Answer
(B)
\(A\) \(B\) \(Y\) \(0\) \(0\) \(1\) \(0\) \(1\) \(0\) \(1\) \(0\) \(1\) \(1\) \(1\) \(1\)
Step-by-step Solution
Detailed explanation
\(Y=A \cdot B+\bar{B}\) \(A\) \(B\) \(Y\) \(0\) \(0\) \(1\) \(0\) \(1\) \(0\) \(1\) \(0\) \(1\) \(1\) \(1\) \(1\)
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