JEE Mains · Physics · STD 11 - 12 . kinetic theory of gases
The relation between root mean square speed \(\left( v _{ rms }\right)\) and most probable speed \(\left( v _{ p }\right)\) for the molar mass \(M\) of oxygen gas molecule at the temperature of \(300\, K\) will be
- A \(v _{ rms }=\sqrt{\frac{2}{3}} v _{ p }\)
- B \(v _{ rms }=\sqrt{\frac{3}{2}} v _{ p }\)
- C \(v _{ rms }= v _{ p }\)
- D \(v _{ rms }=\sqrt{\frac{1}{3}} v _{ p }\)
Answer & Solution
Correct Answer
(B) \(v _{ rms }=\sqrt{\frac{3}{2}} v _{ p }\)
Step-by-step Solution
Detailed explanation
\(v _{ rms }=\sqrt{\frac{3 RT }{ M }} \text { and } v _{ mp }=\sqrt{\frac{2 RT }{ M }}\) Thus \(v _{ rms }=\sqrt{\frac{3}{2}} v _{ mp }\)
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