ExamBro
ExamBro
JEE Mains · Physics · STD 12 - Moving charges and magnetism
  • JEE Mains 2024
  • Hard
  • MCQ

A galvanometer has a resistance of \(50 \Omega\) and allows a maximum current of \(5 \mathrm{~mA}\) to pass. What is the necessary series resistance to connect to convert it to a voltmeter that can measure \(100 \mathrm{~V}\)?

Pick an option to check your answer.
Verified Solution

Answer & Solution

Correct Answer

(C) \(19950 \Omega\)

Step-by-step Solution

Detailed explanation

R= \(\frac{V}{I_g}-R_g=\frac{100}{5 \times 10^{-3}}-50\)

\(=20000-50\)

\(=19950 \Omega\)

Same subject
Explore more questions on app