JEE Mains · Physics · STD 12 -Electromagnetic induction
- JEE Mains 2019
- Hard
- MCQ
A copper wire is wound on a wooden frame, whose shape is that of an equilateral triangle. If the linear dimension of each side of the frame is increased by a factor of \(3\), keeping the number of turns of the coil per unit length of the frame the same, then self inductance of the coil
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Answer & Solution
Correct Answer
(C) increases by a factor of \(3\)
Step-by-step Solution
Detailed explanation
Total length \(L\) will remain constant
\(\mathrm{L}=(3 \mathrm{a}) \mathrm{N} \quad(\mathrm{N}=\text { total tums })\)
And length of winding \(=(d) N=\ell\)
\((d=\text { diameter of wire })\)
Self inductance \(=\mu_{0} \mathrm{n}^{2} \mathrm{A} \ell\)
\(=\mu_{0} n^{2}\left(\frac{\sqrt{3} a^{2}}{4}\right) d N\)
\(\alpha a^{2} N \propto a\)
So self inductance will become \(3\) times.
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