JEE Mains · Physics · STD 11 - 2. motion in straight line
A particle starts with an initial velocity of \(10.0\,ms ^{-1}\) along \(x\)-direction and accelerates uniformly at the rate of \(2.0\,ms ^{-2}\). The time taken by the particle to reach the velocity of \(60.0\,ms ^{-1}\) is \(.......\,s\)
- A \(6\)
- B \(3\)
- C \(30\)
- D \(25\)
Answer & Solution
Correct Answer
(D) \(25\)
Step-by-step Solution
Detailed explanation
\(v=u+a t\) \(60=10+2\,t\) \(t=25\,sec\)
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