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JEE Mains · Physics · STD 12 - 14. Semicondutor electronics
In a given circuit diagram, a \(5 \,{V}\) zener diode along with a series resistance is connected across a \(50 \,V\) power supply. The minimum value of the resistance required, if the maximum zener current is \(90\, {mA}\) will be \(.....\,\Omega .\)
- A \(100\)
- B \(1000\)
- C \(500\)
- D \(50\)
Answer & Solution
Correct Answer
(C) \(500\)
Step-by-step Solution
Detailed explanation
Voltage across \({R}_{{L}}=5\, {V}\) \(\Rightarrow {i}_{2}=\frac{5}{{R}_{{L}}}\) Also voltage across \({R}=50-5=45\) \(volt\) By \(v=i R \Rightarrow R=\frac{v}{i}=\frac{45}{i_{1}+i_{2}}\) \({R}=\frac{45}{90 {m} {A}+\frac{5}{{R}_{{L}}}}\) Current in zener diode is maximum when…
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