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JEE Mains · Physics · STD 12 - Electric charges and fields
  • JEE Mains 2021
  • Hard
  • MCQ

A charge \('q'\) is placed at one corner of a cube as shown in figure. The flux of electrostatic field \(\overrightarrow{ E }\) through the shaded area is ...... .

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Answer & Solution

Correct Answer

(B) \(\frac{ q }{24 \varepsilon_{0}}\)

Step-by-step Solution

Detailed explanation

flux through cube \(=\frac{ q }{8 \epsilon_{0}}\)

flux through surfaces \(ABEH , ADGH , ABCD\) will be zero

\(\phi( EFGH )=\phi( DCFG )=\phi( EBCF )=\frac{1}{3}\left(\frac{ q }{8 \epsilon_{0}}\right)\)

\(=\frac{q}{24 \epsilon_{0}}\)

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