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JEE Mains · Physics · STD 12 -6. Electromagnetic induction

A conducting circular loop made of a thin wire, has area \(3.5 \times 10^{-3}\, m^2\) and resistance \(10\,\Omega \). It is placed perpendicular to a time dependent magnetic field \(B(t) = (0.4\,T)\, sin\, (50\, \pi t)\). The field is uniform in space. Then the net charge flowing through the loop during \(t = 0\, s\) and \(t = 10\, ms\) is close to.......\(mC\)

  1. A \(14\)
  2. B \(7\)
  3. C \(21\)
  4. D \(140\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(140\)

Step-by-step Solution

Detailed explanation

\({\text{B}}({\text{t}}) = 0.4\sin \left( {50\pi \times {{10}^{ - 2}}} \right)\) \( = 0.4\sin \left( {\frac{{50\pi }}{{100}}} \right) = 0.4\) \(\Delta q = \frac{{ - \Delta {\text{Q}}}}{{\text{R}}} = \frac{{\Delta {\text{Q}}}}{{\text{R}}}\)…
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