JEE Mains · Physics · STD 11 - 1. units,dimensions and measurement
The equation of state of a real gas is given by \(\left(\mathrm{P}+\frac{\mathrm{a}}{\mathrm{V}^2}\right)(\mathrm{V}-\mathrm{b})=\mathrm{RT}\), where \(\mathrm{P}, \mathrm{V}\) and \(\mathrm{T}\) are pressure. volume and temperature respectively and \(R\) is the universal gas constant. The dimensions of \(\frac{a}{b^2}\) is similar to that of :
- A \(PV\)
- B \(\mathrm{P}\)
- C \(RT\)
- D \(\mathrm{R}\)
Answer & Solution
Correct Answer
(B) \(\mathrm{P}\)
Step-by-step Solution
Detailed explanation
\( {[\mathrm{P}]=\left[\frac{\mathrm{a}}{\mathrm{V}^2}\right] \Rightarrow[\mathrm{a}]=\left[\mathrm{PV}^2\right]} \) \( \text { And }[\mathrm{V}]=[\mathrm{b}] \)…
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