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JEE Mains · Physics · STD 11 - 10.1, thermonetry,thermal expansion and calorimetry
  • JEE Mains 2022
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  • MCQ

A solid metallic cube having total surface area \(24\;m ^{2}\) is uniformly heated. If its temperature is increased by \(10\,^{\circ} C\), calculate the increase in volume of the cube \(\left(\right.\) Given \(\left.: \alpha=5.0 \times 10^{-4}{ }^{\circ} C ^{-1}\right)\)

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Answer & Solution

Correct Answer

(B) \(1.2 \times 10^{5} cm ^{3}\)

Step-by-step Solution

Detailed explanation

Increase in volume \(\Delta V =\gamma V _{0} \Delta T\)

\(\gamma=3 \alpha\)

So \(\Delta V =(3 \alpha) V _{0} \Delta T\)

Total surface area \(=6 a ^{2}\), where \(a\) is side length \(24=6 a ^{2} \quad a =2 m\)

\(Volume \,V _{0}=(2)^{3}=8 m ^{3}\)

\(\Delta V =\left(3 \times 5 \times 10^{-4}\right)(8) \times 10\)

\(=1.2 \times 10^{5} cm ^{3}\)

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