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JEE Mains · Physics · STD 11 - Kinetic theory of gases
  • JEE Mains 2019
  • Hard
  • MCQ

The specific heats, \(C_P\) and \(C_V\) of a gas of diatomic molecules, \(A\), are given (in units of \(J\, mol^{-1}\, K^{-1}\)) by \(29\) and \(22\), respectively. Another gas of diatomic molecules \(B\), has the corresponding values \(30\) and \(21\). If they are treated as ideal gases, then

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Correct Answer

(D) \(A\) has a vibrational mode but \(B\) has none

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Detailed explanation

For \(A:\)

\(\frac{C_{p}}{C_{v}}=\gamma=1+\frac{2}{f}=\frac{29}{22}\)

It gives \(f=6.3 \approx 6 \quad(3 \text { translational, } 2 \text { rotational and } 1\) vibrational)

For \(B:\)

\(\frac{C_{p}}{C_{v}}=\gamma=1+\frac{2}{f}=\frac{30}{21}\)

\(\Rightarrow \mathrm{f}=4.67\)

\(\Rightarrow \quad \approx 5 \quad(3 \text { translational, } 2\) rotational, no vibrational)

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