JEE Mains · Physics · STD 11 - 12 . kinetic theory of gases
The specific heats, \(C_P\) and \(C_V\) of a gas of diatomic molecules, \(A\), are given (in units of \(J\, mol^{-1}\, K^{-1}\)) by \(29\) and \(22\), respectively. Another gas of diatomic molecules \(B\), has the corresponding values \(30\) and \(21\). If they are treated as ideal gases, then
- A \(A\) has one vibrational mode and \(B\) has two
- B Both \(A\) and \(B\) have a vibrational mode each
- C \(A\) is rigid but \(B\) has a vibrational mode
- D \(A\) has a vibrational mode but \(B\) has none
Answer & Solution
Correct Answer
(D) \(A\) has a vibrational mode but \(B\) has none
Step-by-step Solution
Detailed explanation
For \(A:\) \(\frac{C_{p}}{C_{v}}=\gamma=1+\frac{2}{f}=\frac{29}{22}\) It gives \(f=6.3 \approx 6 \quad(3 \text { translational, } 2 \text { rotational and } 1\) vibrational) For \(B:\) \(\frac{C_{p}}{C_{v}}=\gamma=1+\frac{2}{f}=\frac{30}{21}\) \(\Rightarrow \mathrm{f}=4.67\)…
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