JEE Mains · Physics · STD 11 - 12 . kinetic theory of gases
The kinetic energy of translation of the molecules in 50 g of \(\mathrm{CO}_2\) gas at \(17^{\circ} \mathrm{C}\) is
- A 4205.5 J
- B 4102.8 J
- C 3582.7 J
- D 3986.3 J
Answer & Solution
Correct Answer
(B) 4102.8 J
Step-by-step Solution
Detailed explanation
Kinetic energy of translation \(=\frac{3}{2} n R T\) \(\begin{aligned} & n=\frac{50 \mathrm{~g}}{44 \mathrm{~g}}=\frac{25}{22} \mathrm{~mol} \\ & T=17^{\circ} \mathrm{C}=290 \mathrm{~K} \end{aligned}\) \(\Rightarrow\) Kinetic energy of translation…
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