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JEE Mains · Physics · STD 11 - 7. gravitation
The gravitational field in a region is given by \(\vec E\) \(=(5\,N / kg)\, \hat i + (12\,N / kg)\,\hat j\) If the potential at the origin is taken to be zero, then the ratio of the potential at the points \((12\,m, 0)\) and \((0, 5\,m)\) is
- A Zero
- B \(1\)
- C \(\frac{{144}}{{25}}\)
- D \(\frac{{25}}{{144}}\)
Answer & Solution
Correct Answer
(B) \(1\)
Step-by-step Solution
Detailed explanation
From question, \({E_x} = 5\,N/kg\,and\,{E_y} = 12\,N/kg\) Gravitational potential \(=Gravitational\, field\times\,distance\) \(\therefore {V_{\left( {12m,0} \right)}} = {E_x} \times 12\,J/kg\) \(and\,{V_{\left( {0.5m} \right)}} = {E_y} \times 5\,\,J/kg\)…
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