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JEE Mains · Physics · STD 11 - Gravitation
- JEE Mains 2013
- Hard
- MCQ
The gravitational field in a region is given by \(\vec E\) \(=(5\,N / kg)\, \hat i + (12\,N / kg)\,\hat j\) If the potential at the origin is taken to be zero, then the ratio of the potential at the points \((12\,m, 0)\) and \((0, 5\,m)\) is
Pick an option to check your answer.
Answer & Solution
Correct Answer
(B) \(1\)
Step-by-step Solution
Detailed explanation
From question,
\({E_x} = 5\,N/kg\,and\,{E_y} = 12\,N/kg\)
Gravitational potential
\(=Gravitational\, field\times\,distance\)
\(\therefore {V_{\left( {12m,0} \right)}} = {E_x} \times 12\,J/kg\)
\(and\,{V_{\left( {0.5m} \right)}} = {E_y} \times 5\,\,J/kg\)
\(\left( {Give\,:\,potential\,at\,the\,origin\,is\,zero} \right)\)
\(\therefore \frac{{{V_{\left( {12\,m,0} \right)}}}}{{{V_{\left( {0,5m} \right)}}}} = \frac{{{E_x} \times 12}}{{{E_y} \times 5}} = \frac{{5 \times 12}}{{12 \times 5}} = 1\)
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