JEE Mains · Physics · STD 12 -6. Electromagnetic induction
A power transmission line feeds input power at \(2300\,V\) to a step down transfonner with its primary windings having \(4000\) turns, giving the output power at \(230\,V.\) If the current in the primary of the transformer is \(5\,A,\) and its efficiency is \(90\%,\) the output current would be......\(A\)
- A \(20\)
- B \(40\)
- C \(45\)
- D \(25\)
Answer & Solution
Correct Answer
(C) \(45\)
Step-by-step Solution
Detailed explanation
Given \(: V_{P}=2300\, \mathrm{V}, V_{s}=230\, \mathrm{V}, I_{P}=5\, \mathrm{A}\) \(\eta=90 \%=0.9\) Efficiency \(\eta=0.9=\frac{P_{s}}{P_{p}} \Rightarrow P_{s}=0.9 P_{p}\)…
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