JEE Mains · Physics · STD 12 - 1. Electric charges and fields
A cone of base radius \(R\) and height \(h\) is located in a uniform electric field \(\vec E\) parallel to its base. The electric flux entering the cone is
- A \(\frac{1}{2}\,EhR\)
- B \(E h R\)
- C \(2\, E h R\)
- D \(4\, E h R\)
Answer & Solution
Correct Answer
(B) \(E h R\)
Step-by-step Solution
Detailed explanation
Electric flux, \(\phi \, = E \,(ds)\, cos\, \theta\) \(= E \,(hR)\, cos\, 0^o\, = EhR\)
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