JEE Mains · Physics · STD 12 - Wave optics
- JEE Mains 2022
- Medium
- Numerical
In young's double slit experiment performed using a monochromatic light of wavelength \(\lambda\), when a glass plate \((\mu=1.5)\) of thickness \(x \lambda\) is introduced in the path of the one of the interfering beams, the intensity at the position where the central maximum occurred previously remains unchanged. The value of \(x\) will be..........
Pick an option to check your answer.
Answer & Solution
Correct Answer
(B) \(2\)
Step-by-step Solution
Detailed explanation
Path difference at \(O =(\mu-1) t\).
If the intensity at \(O\) remains (maximum) unchanged, path difference must be \(n \lambda\).
\(\Rightarrow(\mu-1) t = n \lambda\)
\((1.5-1) x \lambda= n \lambda\)
\(\Rightarrow x =2 n\)
For \(n =1, x =2\)
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