JEE Mains · Physics · STD 11 - 6. system of particles and rotational motion
A square Lamina OABC of length 10 cm is pivoted at 'O'. Forces act at Lamina as shown in figure. If Lamina remains stationary, then the magnitude of F is :
- A 20 N
- B 0 (zero)
- C 10 N
- D \(10 \sqrt{2} \mathrm{~N}\)
Answer & Solution
Correct Answer
(C) 10 N
Step-by-step Solution
Detailed explanation
Since the lamina is equilibrium. \(\therefore \mathrm{F}_{\mathrm{net}}=0 \& \tau_{\mathrm{net}}=0\) \(\mathrm{T}_{\mathrm{o}}=10 \ell-\mathrm{F} \ell \Rightarrow \mathrm{F}=10 \mathrm{~N}\)
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