JEE Mains · Physics · STD 12 - 4. Moving charges and magnetism
A current of \(200\ \mu \mathrm{A}\) deflects the coil of a moving coil galvanometer through \(60^{\circ}\). The current to cause deflection through \(\frac{\pi}{10}\) radian is:
- A \(30 \ \mu \mathrm{A}\)
- B \(120\ \mu \mathrm{A}\)
- C \(60 \ \mu \mathrm{A}\)
- D \(180\ \mu \mathrm{A}\)
Answer & Solution
Correct Answer
(C) \(60 \ \mu \mathrm{A}\)
Step-by-step Solution
Detailed explanation
\(i \propto \theta\) (angle of deflection) \( \therefore \frac{i_2}{i_1}=\frac{\theta_2}{\theta_1} \Rightarrow \frac{i_2}{200 \mu \mathrm{A}}=\frac{\pi / 10}{\pi / 3}=\frac{3}{10}\) \( \Rightarrow \mathrm{i}_2=60\ \mu \mathrm{A}\)
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