JEE Mains · Chemistry · STD 11 - 2. structure of atom
Wavenumber for a radiation having \(5800 \mathring A\) wavelength is \(x \times 10 \mathrm{~cm}^{-1}\). The value of \(x\) is _______.
- A \(1724\)
- B \(1725\)
- C \(1727\)
- D \(1730\)
Answer & Solution
Correct Answer
(A) \(1724\)
Step-by-step Solution
Detailed explanation
\(\bar{v} \text { (wave no.) }=\frac{1}{\lambda}=\frac{1}{5800 \times 10^{-8} \mathrm{~cm}}=17241\) OR \(1724 \times 10 \mathrm{~cm}^{-1} \Rightarrow \mathrm{x}=1724\)
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