JEE Mains · Physics · STD 11 - 4.1 newtons laws of motion
A lift of mass \(1600\) kg is supported by thick iron wire. If the maximum stress which the wire can withstand is \(4 \times 10^8\) N/m\(^2\) and its radius is \(4\) mm, then maximum acceleration the lift can take is _______ m/s\(^2\). (take \(g = 10\) m/s\(^2\) and \(\pi = 3.14\))
- A \(2.56\)
- B \(3.89\)
- C \(4.32\)
- D \(5.16\)
Answer & Solution
Correct Answer
(A) \(2.56\)
Step-by-step Solution
Detailed explanation
Maximum stress \(\sigma_{max} = 4 \times 10^8\) N/m\(^2\) Radius of wire \(r = 4 \times 10^{-3}\) m Mass of lift \(m = 1600\) kg Maximum tension the wire can withstand is given by: \(T_{max} = \sigma_{max} \times \pi r^2\)…
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