JEE Mains · Chemistry · STD 12 - 2. Electrochemistry
The mass of zinc produced by the electrolysis of zinc sulphate solution with a steady current of \(0.015\ A\) for \(15\) minutes is _______ \(\times 10^{-4} \mathrm{~g}\).\((\) Atomic mass of zinc \(=65.4 \ \mathrm{amu})\)
- A \(47\)
- B \(46\)
- C \(49\)
- D \(41\)
Answer & Solution
Correct Answer
(B) \(46\)
Step-by-step Solution
Detailed explanation
\( \mathrm{Zn}^{+2}+2 \mathrm{e}^{-} \longrightarrow \mathrm{Zn} \) \( \mathrm{W}=\mathrm{Z} \times \mathrm{i} \times \mathrm{t} \) \( =\frac{65.4}{2 \times 96500} \times 0.015 \times 15 \times 60 \) \( =45.75 \times 10^{-4} \mathrm{gm}\)
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