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JEE Mains · Physics · STD 11 - 7. gravitation

The percentage decrease in the weight of a rocket, when taken to a height of \(32 km\) above the surface of earth will, be\(.....\%\) (Radius of earth \(=6400\,km\) )

  1. A \(1\)
  2. B \(3\)
  3. C \(4\)
  4. D \(0.5\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(1\)

Step-by-step Solution

Detailed explanation

Acceleration due to gravity at a height \(h << R\) is \(g ^{\prime}= g \left(1-\frac{2 h }{ R }\right)\) \(\therefore \frac{\Delta g }{ g }=\frac{2 h }{ R }\) \(\Rightarrow \frac{\Delta g }{ g } \times 100=\frac{2 h }{ R } \times 100\)…
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