ExamBro
ExamBro
JEE Mains · Physics · STD 11 - Gravitation
  • JEE Mains 2022
  • Medium
  • Numerical

The percentage decrease in the weight of a rocket, when taken to a height of \(32 km\) above the surface of earth will, be\(.....\%\) (Radius of earth \(=6400\,km\) )

Pick an option to check your answer.
Verified Solution

Answer & Solution

Correct Answer

(A) \(1\)

Step-by-step Solution

Detailed explanation

Acceleration due to gravity at a height \(h << R\) is

\(g ^{\prime}= g \left(1-\frac{2 h }{ R }\right)\)

\(\therefore \frac{\Delta g }{ g }=\frac{2 h }{ R }\)

\(\Rightarrow \frac{\Delta g }{ g } \times 100=\frac{2 h }{ R } \times 100\)

\(=2 \times \frac{32}{6400} \times 100=1 \%\)

Same subject
Explore more questions on app
From JEE Mains
Explore more questions on app