JEE Mains · Chemistry · STD 11 - 2. structure of atom
Total number of ions from the following with noble gas configuration is__________. \( \mathrm{Sr}^{2+}(\mathrm{Z}=38), \mathrm{Cs}^{+}(\mathrm{Z}=55), \mathrm{La}^{2+}(\mathrm{Z}=57) \mathrm{Pb}^{2+} \) \( (\mathrm{Z}=82), \mathrm{Yb}^{2+}(\mathrm{Z}=70) \text { and } \mathrm{Fe}^{2+}(\mathrm{Z}=26)\)
- A \(2\)
- B \(7\)
- C \(9\)
- D \(11\)
Answer & Solution
Correct Answer
(A) \(2\)
Step-by-step Solution
Detailed explanation
\( \text { Noble gas configuration }=\mathrm{ns}^2 \mathrm{np}^6 \) \( {\left[\mathrm{Sr}^{2+}\right]=[\mathrm{Kr}\rfloor} \) \( {\left[\mathrm{Cs}^{+}\right]=[\mathrm{Xe}]} \) \( {\left[\mathrm{Yb}^{2+}\right]=[\mathrm{Xe}] 4 \mathrm{f}^{14}}\)…
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