JEE Mains · Chemistry · STD 11 - 2. structure of atom
Arrange the following orbitals in decreasing order of energy ? \((A)\) \(n =3,1=0, m =0\) \((B)\) \(n =4, l =0, m =0\) \((C)\) \(n =3, l =1, m =0\) \((D)\) \(n =3, l =2, m =1\) The correct option for the order is :
- A \(B > D > C > A\)
- B \(D > B > C > A\)
- C \(A > C > B > D\)
- D \(D > B > A > C\)
Answer & Solution
Correct Answer
(B) \(D > B > C > A\)
Step-by-step Solution
Detailed explanation
\((A)\) \(n =3 ; 1=0 ; m =0 ; 3 s\) orbital \((B)\) \(n =4 ; 1=0 ; m =0 ; 4 s\) orbital \((C)\) \(n =3 ; 1=1 ; m =0 ; 3 p\) orbital \((D)\) \(n =3 ; 1=2 ; m =0 ; 3 d\) orbital As per Hund's rule energy is given by \(( n +l)\) value. If value of \(( n +l)\) remains same then…
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