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JEE Mains · Chemistry · STD 11 - 7. Redox reactions

The group 14 elements A and B have the first ionisation enthalpy values of \(708\) and \(715 \mathrm{~kJ} \mathrm{~mol}^{-1}\) respectively. The above values are lowest among their group members. The nature of their ions \(\mathrm{A}^{2+}\) \(\mathrm{B}^{4+}\) respectively is _______.

  1. A both reducing
  2. B both oxidising
  3. C reducing and oxidising
  4. D oxidising and reducing
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Answer & Solution

Correct Answer

(C) reducing and oxidising

Step-by-step Solution

Detailed explanation

As per given information of ionisation energy \(\mathrm{A}=\mathrm{Sn} \& \mathrm{~B}=\mathrm{Pb}\) \(\begin{aligned} & \mathrm{A}^{+2}=\mathrm{Sn}^{2+}=\text { Reducing agent } \\ & \mathrm{B}^{+4}=\mathrm{Pb}^{+4}=\text { Oxidising agent }\end{aligned}\)
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