JEE Mains · Chemistry · STD 11 - 2. structure of atom
The correct set of four quantum numbers for the valence electron of rubidium atom \((Z=37)\) is _______.
- A \(5,0,0,+\frac{1}{2}\)
- B \(5,0,1,+\frac{1}{2}\)
- C \(5,1,0,+\frac{1}{2}\)
- D \(5,1,1,+\frac{1}{2}\)
Answer & Solution
Correct Answer
(A) \(5,0,0,+\frac{1}{2}\)
Step-by-step Solution
Detailed explanation
\( \mathrm{Rb}=[\mathrm{Kr}] 5 \mathrm{~s}^1 \) \( \mathrm{n}=5 \) \( l=0 \) \( \mathrm{~m}=0 \) \( \mathrm{~s}=+1 / 2 \text { or }-1 / 2\)
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