JEE Mains · Chemistry · STD 11 - 1. Some basic concept of chemistry
The density of a monobasic strong acid (Molar mass \(24.2\,g\,mol )\) is \(1.21\,kg\,L\). The volume of its solution required for the complete neutralization of \(25\,mL\) of \(0.24\,M\,NaOH\) is \(..............\times 10^{-2}\,mL\) (Nearest integer)
- A \(6\)
- B \(12\)
- C \(3\)
- D \(24\)
Answer & Solution
Correct Answer
(B) \(12\)
Step-by-step Solution
Detailed explanation
millimole of \(NaOH =0.24 \times 25\) \(\therefore \quad \text { millimole of acid }=0.24 \times 25\) \(\Rightarrow \quad \text { mass of acid }=0.24 \times 25 \times 24.2\,mg\) \(\text { for pure acid, }\) \(\qquad V =\frac{ w }{ d } ;( d =1.21\,kg / L =1.21\,g / ml )\)…
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