JEE Mains · Chemistry · STD 11 - 9. Hydricarbon
An alkane \((Y)\) requires \(8\) moles of oxygen for complete combustion and on chlorination with Cl\(_2\)/h\(\nu\), \((Y)\) gives only one monochlorinated product \((Z)\). The total number of primary carbon atoms in \((Y)\) is __________.
- A 2
- B 4
- C 5
- D 7
Answer & Solution
Correct Answer
(B) 4
Step-by-step Solution
Detailed explanation
The general formula of an alkane is \(C_n H_{2n+2}\). The balanced chemical equation for the complete combustion of an alkane is: \(C_n H_{2n+2} + \left(\dfrac{3n+1}{2}\right) O_2 \rightarrow n CO_2 + (n+1) H_2O\) Given that \(8\) moles of oxygen are required for complete…
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