JEE Mains · Physics · STD 11 - Thermodynamics
- JEE Mains 2023
- Medium
- Numerical
Consider two containers \(A\) and \(B\) containing monoatomic gases at the same Pressure \((P)\), Volume \((V)\) and Temperature \((T)\). The gas in \(A\) is compressed isothermally to \(\frac{1}{8}\) of its original volume while the gas \(B\) is compressed adiabatically to \(\frac{1}{8}\) of its original volume. The ratio of final pressure of gas in \(B\) to that of gas in \(A\) is ...........
Pick an option to check your answer.
Answer & Solution
Correct Answer
(D) \(4\)
Step-by-step Solution
Detailed explanation
Isothermal process, \(T =\) constant
\(PV =n R T=\text { constant }\)
\(P _1 V_1= P _2 V_2\)
\(PV = P _{ A }( V / 8)\)
\(P _{ A }=8 P\)
Adiabatic process, PV \(\gamma=\) constant \(\gamma\) for monoatomic gas is \(\frac{5}{3}\).
\(P _1 V _1^\gamma= P _2 V _2^\gamma\)
\(\frac{ P _{ B }}{ P }=\left(\frac{ V _1}{ V _2}\right)^\gamma=\left(\frac{ V }{ V / 8}\right)^{\frac{5}{3}}\)
\(P _{ B }=32 P\)
\(\frac{ P _{ B }}{ P _{ A }}=\frac{32 P }{8 P }=4\)
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