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JEE Mains · Physics · STD 11 - Thermodynamics
  • JEE Mains 2023
  • Medium
  • Numerical

Consider two containers \(A\) and \(B\) containing monoatomic gases at the same Pressure \((P)\), Volume \((V)\) and Temperature \((T)\). The gas in \(A\) is compressed isothermally to \(\frac{1}{8}\) of its original volume while the gas \(B\) is compressed adiabatically to \(\frac{1}{8}\) of its original volume. The ratio of final pressure of gas in \(B\) to that of gas in \(A\) is ...........

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Answer & Solution

Correct Answer

(D) \(4\)

Step-by-step Solution

Detailed explanation

Isothermal process, \(T =\) constant

\(PV =n R T=\text { constant }\)

\(P _1 V_1= P _2 V_2\)

\(PV = P _{ A }( V / 8)\)

\(P _{ A }=8 P\)

Adiabatic process, PV \(\gamma=\) constant \(\gamma\) for monoatomic gas is \(\frac{5}{3}\).

\(P _1 V _1^\gamma= P _2 V _2^\gamma\)

\(\frac{ P _{ B }}{ P }=\left(\frac{ V _1}{ V _2}\right)^\gamma=\left(\frac{ V }{ V / 8}\right)^{\frac{5}{3}}\)

\(P _{ B }=32 P\)

\(\frac{ P _{ B }}{ P _{ A }}=\frac{32 P }{8 P }=4\)

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