JEE Mains · Chemistry · STD 11 - 6.2. Equilibrium - II (icon Equilibrium)
At \(298\,K\), the solubility of silver chloride in water is \(1.434 \times 10^{-3}\,g\,L ^{-1}\). The value of \(-\log K _{ sp }\) for silver chloride is \(........\) (Given mass of \(Ag\) is \(107.9\,g\,mol ^{-1}\) and mass of \(Cl\) is \(35.5\,g\,mol ^{-1}\) )
- A \(9\)
- B \(8\)
- C \(10\)
- D \(7\)
Answer & Solution
Correct Answer
(C) \(10\)
Step-by-step Solution
Detailed explanation
\(AgCl ( s ) \rightarrow Ag _{ S }^{+} \text {(aq.) }+ Cl ^{-} \text {(aq.) }\) \(K _{ sp }= S ^2=\left(\frac{1.43}{143.4} \times 10^{-3}\right)^2=10^{-10}\) \(-\log K _{ sp }=10\)
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