JEE Mains · Chemistry · STD 12 - 3. Chemical kinetics
For the given first order reaction \(\text { A } \rightarrow \text { B }\) the half life of the reaction is \(0.3010\,min\). The ratio of the initial concentration of reactant to the concentration of reactant at time \(2.0\,min\) will be equal to \(........\) (Nearest integer)
- A \(110\)
- B \(112\)
- C \(100\)
- D \(113\)
Answer & Solution
Correct Answer
(C) \(100\)
Step-by-step Solution
Detailed explanation
\(A \rightarrow B \quad t _{1 / 2}=0.3010\,min\) \(A _{0} / A _{ t }\) at time \(2\,min =?\) \(K =\frac{2.303}{ t } \log \left[\frac{ A _{0}}{ A _{ t }}\right]\) \(\frac{0 \cdot 693}{ t _{\frac{1}{2}}}=\frac{2 \cdot 303}{2} \log \left(\frac{ A _{0}}{ A _{ t }}\right)\) Or…
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