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JEE Mains · Chemistry · STD 12 - 3. Chemical kinetics

Assuming \(1\,\mu\,g\) of trace radioactive element \(X\) with a half life of \(30\) years is absorbed by a growing tree. The amount of \(X\) remaining in the tree after \(100\) years is \(\times 10^{-1}\,\mu\,g\) \([ Given : \ln 10=2.303 ; \log 2=0.30]\)

  1. A \(0\)
  2. B \(2\)
  3. C \(1\)
  4. D \(3\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(1\)

Step-by-step Solution

Detailed explanation

\(t =\frac{1}{\lambda} \ln \left(\frac{ a }{ a - x }\right)\) \(100=\frac{30}{\ln 2} \ln \left(\frac{1}{ w }\right)\) \(\frac{1}{ w }=10\) \(W =0.1 \times\,\mu\,g\) Ans. \(1 \times 10^{-1}\,\mu\,g\)