JEE Mains · Chemistry · STD 12 - 3. Chemical kinetics
Assuming \(1\,\mu\,g\) of trace radioactive element \(X\) with a half life of \(30\) years is absorbed by a growing tree. The amount of \(X\) remaining in the tree after \(100\) years is \(\times 10^{-1}\,\mu\,g\) \([ Given : \ln 10=2.303 ; \log 2=0.30]\)
- A \(0\)
- B \(2\)
- C \(1\)
- D \(3\)
Answer & Solution
Correct Answer
(C) \(1\)
Step-by-step Solution
Detailed explanation
\(t =\frac{1}{\lambda} \ln \left(\frac{ a }{ a - x }\right)\) \(100=\frac{30}{\ln 2} \ln \left(\frac{1}{ w }\right)\) \(\frac{1}{ w }=10\) \(W =0.1 \times\,\mu\,g\) Ans. \(1 \times 10^{-1}\,\mu\,g\)
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